So start with R8 and R10, which are in series. You will get a combined resistance of 12 Ohms. Then, this combined 12 Ohm resistor is in parallel with the R9 resistor, and using the parallel resistors formula, you will get a combined resistance of 4 Ohms. Then, that last 4 Ohm resistor will be in series with R7, an 8 Ohm resistor, so 4 + 8 = 12 Ohms. Then, this last 12 Ohm resistor will be parallel to resistor R6. Again, use the parallel resistors formula and you will again get a combined resistor of 4 Ohms. Then, this 4 Ohm resistor will be in series with the R5 resistor (with 4 Ohms), giving a combined resistor of 8 Ohms. Then, this 8 Ohm resistor will be in parallel with the R4 resistor, which is also 8 Ohms. Using the parallel resistors formula again, you get 4 Ohms. Then, this 4 Ohm resistor will be in series with the R3 resistor, which is also 4 Ohms. Using the series resistors formula, you will get 8 Ohms, and then this 8 Ohm resistor will be in parallel with the last 8 Ohm resistor, which is R2. Use the parallel resistor formula again and you will get a combined resistance of 4 Ohms. Finally, there is a simple loop and you can just add the last 4 Ohm resistor you calculated with R1, which is 6 Ohms, giving you a final Req of 10 Ohms.
We got that the equivalent resistance between the terminals is 10 ohms.
The trick is to realize that R8 and R10 are in series. These two resistors are in parallel with R9. This allows us to work our way back to the two terminals. Let us know if you have any questions about how to simplify.
So start with R8 and R10, which are in series. You will get a combined resistance of 12 Ohms. Then, this combined 12 Ohm resistor is in parallel with the R9 resistor, and using the parallel resistors formula, you will get a combined resistance of 4 Ohms. Then, that last 4 Ohm resistor will be in series with R7, an 8 Ohm resistor, so 4 + 8 = 12 Ohms. Then, this last 12 Ohm resistor will be parallel to resistor R6. Again, use the parallel resistors formula and you will again get a combined resistor of 4 Ohms. Then, this 4 Ohm resistor will be in series with the R5 resistor (with 4 Ohms), giving a combined resistor of 8 Ohms. Then, this 8 Ohm resistor will be in parallel with the R4 resistor, which is also 8 Ohms. Using the parallel resistors formula again, you get 4 Ohms. Then, this 4 Ohm resistor will be in series with the R3 resistor, which is also 4 Ohms. Using the series resistors formula, you will get 8 Ohms, and then this 8 Ohm resistor will be in parallel with the last 8 Ohm resistor, which is R2. Use the parallel resistor formula again and you will get a combined resistance of 4 Ohms. Finally, there is a simple loop and you can just add the last 4 Ohm resistor you calculated with R1, which is 6 Ohms, giving you a final Req of 10 Ohms.
Hey Sahil,
We got that the equivalent resistance between the terminals is 10 ohms.
The trick is to realize that R8 and R10 are in series. These two resistors are in parallel with R9. This allows us to work our way back to the two terminals. Let us know if you have any questions about how to simplify.